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-9u-2=-4u^2
We move all terms to the left:
-9u-2-(-4u^2)=0
We get rid of parentheses
4u^2-9u-2=0
a = 4; b = -9; c = -2;
Δ = b2-4ac
Δ = -92-4·4·(-2)
Δ = 113
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{113}}{2*4}=\frac{9-\sqrt{113}}{8} $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{113}}{2*4}=\frac{9+\sqrt{113}}{8} $
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